Question

Is this correct?
asymptotes

Answer 1

you can find the vertical asymptote of each of those by setting the bottom equal to 0
you can find the horizontal asymptote by looking at the number that is left over from the part that can't be 0
like 3/(x-4) or 3/(x+4) cannot be 0 for any x
because the numerator cannot be 0
so the horizontal asymptote for either 3/(x-4) or 3/(x+4) is y=0
you can look at your choices and translate that horizontal asymptote either up two due to +2
or down two due to the -2

Answer 2

you could also graph this on a graphing calculator to find your asymptotes :)

Answer 3

@quickstudent do you understand what freckles said?

Answer 4

well, I didn't get the +2 -2 part.

Answer 5

well, I didn't get the +2 -2 part.

Answer 6

\[\frac{3}{x \pm 4} \neq 0\]
do you understand that this is true?

Answer 7

\[\frac{3}{x \pm 4} \neq 0 \text{ so horizontal asymptote is } y=0 \\ \text{ what if you subtract 4 on both sides } \\ \frac{3}{x \pm 4 }-4 \neq -4 \text{ so horizontal asymptote is } y=-4 \]

Answer 8

That last is just an example

Answer 9

in general if you have this :
\[f(x)=\frac{a}{bx + c}+n \text{ the horizontal asymptote is } y=n \\ \text{ and the vertical asymptote is } x=\frac{-c}{b} \text{ assuming } a, b \neq 0\]