A tin can (right circular cylinder) with top and bottom is to have volume V . What dimensions (the radius of the bottom and the height) give the minimum total surfacearea?

Question

anonymous · Answer

I am told that $$r=\sqrt[3]{V/(2 \pi)}$$ , and have been able to successfully show that by solving the volume formula for h and using that int he surface area formula...
now, using that r, can someone show me how to get h equal to 2r, which is what the professor has provided.

anonymous · Answer

$$h=2\sqrt[3]{V/(2 \pi)}$$ is given, and I'm having difficulty showing the steps to arrive at that answer