prove sec θ / tan θ = csc θ
do we have \[\sec\theta =\frac{1}{\sin \theta}\] and \[\tan \theta =\frac{\sin \theta}{\cos \theta }\] the rest is just multiplying and canceling
so we have now \[\frac{1}{\cos \theta }\times \frac{\cos \theta}{\sin \theta}\]
I need it step by step with reasons like what identities you used and everything
oh correction sec =1/cos not 1/sin typo :P
the identities involved are above just correct the first line to sec=/1cos
\(\tt sec \theta = \frac{1}{cos \theta} ~and~cosec \theta = \frac{1}{sin \theta}\) That's it. Now all you have to do is replace things like following, \(\huge \tt \frac{sec \theta}{tan \theta} = \frac{1/cos \theta}{sin \theta / cos \theta} = ? \)
im still not understanding the reasons part of this. I have a chart I have to fill out
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