Question

Pre-Calc: Need Help
Fan + Medal for most helpful person!

Eliminate the parameter.

x = square root of t, y = 4t + 1

y = 4square root of x + 1, x ≥ 0
y = 4square root of x - 1, x ≥ 0
y = 4x2 - 1
y = 4x2 + 1

Answer 1

\[x=\sqrt{t}\\x^2=t\] is a start

Answer 2

so would it be the 4th answer? y= 4X^2 +1?

Answer 3

yup

Answer 4

and does that make this one:
Eliminate the parameter.

x = t2 + 3, y = t2 - 2

y = x-5?

Answer 5

yup

Answer 6

Do you know this last one?
Eliminate the parameter.

x = 5 cos t, y = 5 sin t

Answer 7

you get rid t of by square both sides of them, add them together and use trig cos^2 +sin^2 =1to simplify the stuff

Answer 8

so how would we get both sin and cos in the same equation?

Answer 9

x^2 =25cos^2t
y^2= 25sin^2t
----------------
x^2+y^2 =25 (cos^2 t + sin^2 t) =25
that is your final answer.

Answer 10

thanks

Answer 11

ok