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Improper integral
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\[\int\limits_{0}^{2} \frac{ 2x+1 }{ x^2+x-6 } dx\]
looks like a set up for a u - sub try \(u=x^2+x-6\)
Yeah, I have that
\[\lim_{b \rightarrow \infty} [\ln|x^2+x-6|]\] from 0 to b
where does the infinity come from?
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That's a typo, oops. supposed to be a 2
\[\ln |b^2 + b -6| - \ln|6|\] I have that, and the answer is -infinity, I'm confused on how that's the answer.
@satellite73 can you help?
HI!!
what are the limits of integration?
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0 to b
to b??
oooh i see it is an improper integral since 2 is a zero of the denominator
yeah, its improper
rather \[\lim_{b \rightarrow 2} [\ln|b^2+b-6|]\]
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on account of you cannot take the log of zero
Thanks
\[\color\magenta\heartsuit\]
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