Question

Will give medals :)

Find the inverse of the function. Determine whether the inverse is a function.

f(x) = (2x - 3)^2

Answer 1

solve \[x=(y-3)^2\] for \(y\) in two steps

Answer 2

but be careful because the first step is
\[\pm\sqrt{x}=y-3\] and the \(\pm\) tells you it is not a function

Answer 3

I honestly don't know how to start the next step.

Answer 4

well i read the problem incorrectly

Answer 5

\[x=(2y-3)^2\] so
\[\pm\sqrt{x}=2y-3\]

Answer 6

then add 3 and divide by 2

Answer 7

\[\pm\sqrt{x}+3=2y\\
y=\frac{\pm\sqrt{x}+3}{2}\]

Answer 8

That't not an inverse right?

Answer 9

thanks for your help btw :)

Answer 10

hi!!

Answer 11

what @satellite73 wrote is an inverse, it is just not a function

Answer 12

Thank you @misty1212 !

Answer 13

\[\color\magenta\heartsuit\]