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Mathematics 21 Online
OpenStudy (anonymous):

What is the solution of the equation? To follow

OpenStudy (anonymous):

\[3\sqrt[5]{(x+2)^{3}}+3=27\]

OpenStudy (anonymous):

\[3\sqrt[5]{(x+2)^{2}}+3=27\] \[3\sqrt[5]{(x+2)^{3}}=24\] \[\sqrt[5]{(x+2)^{3}}=8\] but not sure where to go from here or if I'm right up to here

OpenStudy (hitaro9):

So, if you made this a bit simpler, say sqrt(x) = 8 How would you solve that?

OpenStudy (anonymous):

square both sides

OpenStudy (raden_zaikaria):

false

OpenStudy (anonymous):

huh

OpenStudy (raden_zaikaria):

power of three both of side

OpenStudy (anonymous):

not 5 since the index is 5

OpenStudy (hitaro9):

Why power of 3?

OpenStudy (raden_zaikaria):

sorry hehe

OpenStudy (raden_zaikaria):

power of five

OpenStudy (hitaro9):

Okay...

OpenStudy (hitaro9):

So just like how you would square it if it were sqrt(x) = 8

OpenStudy (hitaro9):

You raise both sides to the 5th power

OpenStudy (raden_zaikaria):

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