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Which of the following best defines
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Square root of 16 Cube root of 4 Square root of 4 Cube root of 16
\(b^{n/m} = (m\sqrt{b})^n = \sqrt[m]{b^n}\)
Sorry that should be \((\sqrt[m]{b})^n\)
Anyway, can you change it to that form? @Legends
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So its \[4\sqrt{3^{2}}\]
No..
\(b^{\dfrac{n}{m}} = (\sqrt[m]{b})^n = \sqrt[m]{b^n}\)
Try again
In this case: b = 4 n = 2 m = 3
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2/4*3
6
No..
\(4^{\dfrac{2}{3}} \rightarrow \sqrt[3]{4^2}\)
Can you simplify \(4^2\)?
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Yes
it would 4
Um..no.. \(4^2 \rightarrow 4 \times 4\)
4*4=16 16/4=4
16 is correct..but we don't divide by 4..
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Oh ok I see what you did
So we have: \(\sqrt[3]{16}\)
That's our simplified answer..
So it would be square root of 16?
Thanks @iGreen
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The CUBE ROOT of 16.
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