A 2.50 kg ball moving at 7.50 m/s is caught by a 70.0 kg man while the man is standing on ice. How fast will the man / ball combination be moving after the ball is caught by the man?

***How would I do this problem? Thank you!

Question

A 2.50 kg ball moving at 7.50 m/s is caught by a 70.0 kg man while the man is standing on ice. How fast will the man / ball combination be moving after the ball is caught by the man?

***How would I do this problem? Thank you!

ganeshie8 · Answer

you may use conservation of momentum $$\large \rm{m_1v_1 = m_2 v_2}$$

ganeshie8 · Answer

$$\large \rm{2.5\times 7.5 = 70v_2}$$

solve $\rm{v_2}$

anonymous · Answer

I can help u

phi · Answer

ball caught by a man 
so mass2 is the sum of the man and ball.
in other words
$$ m_1 v_1 = (m_1 + m_2) v_2 \ 2.5 \ kg \cdot 7.5 \ m/s= (2.5 + 70) \ kg \cdot v_2 $$

anonymous · Answer

okay, thank you all!!

so would it be v2=0.267857?

or is it v2=0.25862? not sure!

and i round it to v2=0.26? and so this is how fast? 0.26 m/s ?