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Mathematics 11 Online
OpenStudy (anonymous):

4. Evaluate 10∑n=2 25(0.3)^n-1 5. Given the sequence in the table below, determine the sigma notation of the sum for term 4 through term 15. n a^n 1 5 2 -10 3 20

OpenStudy (anonymous):

@madmoiselle_sarcasm @Agl202 @madmoiselle_sarcasm

OpenStudy (anonymous):

Sorry not doing that math yet.

OpenStudy (anonymous):

Oh dear my future ahhh

OpenStudy (anonymous):

@madmoiselle_sarcasm lol thanks anyways

OpenStudy (anonymous):

@math

OpenStudy (anonymous):

You're welcome :)

OpenStudy (anonymous):

@mickyboy0202 @Mendicant_Bias @TheEdwardsFamily @logan420 @DiamondBear3299

OpenStudy (minecraft40952):

ummm sorry i dont know this im still in pre algebra

OpenStudy (anonymous):

aww, thanks anyways lol

OpenStudy (anonymous):

id like step by step help , because the lesson doent have an example for these 2

OpenStudy (anonymous):

@perl can you help me?

OpenStudy (perl):

im having trouble reading your question

OpenStudy (anonymous):

is it the way i typed it?

OpenStudy (perl):

Is this the question? $$ \Large \sum_{n=2}^{10} n $$

OpenStudy (anonymous):

yes~ and right next to it is 25(0.3)^n+1

OpenStudy (perl):

$$ \Large \sum_{n=2}^{10} n= 2 + 3 + 4 + 5+ 6 + 8 + 9 + 10 $$

OpenStudy (anonymous):

=47 But the question is this exactly ∑n=210n 25(0.3)^n+1

OpenStudy (anonymous):

@perl ?

OpenStudy (perl):

yes

OpenStudy (perl):

can you take a screenshot of the assignment, or upload it

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (perl):

thanks

OpenStudy (perl):

$$ \large \sum_{n=2}^{10}25 (0.3)^{n+1} = 0.96426673425 $$

OpenStudy (anonymous):

would you mind telling me how you got that answer?

OpenStudy (perl):

I used this http://www.wolframalpha.com/input/?i= \sum_{n%3D2}^{10}25+%280.3%29^{n%2B1}

OpenStudy (perl):

copy and paste that link

OpenStudy (anonymous):

how bout number 5?

OpenStudy (anonymous):

anks on number 4 really appreciated :)

OpenStudy (anonymous):

and thanks *

OpenStudy (anonymous):

@perl are you still there? lol

OpenStudy (perl):

one moment be right back

OpenStudy (anonymous):

ok

OpenStudy (perl):

we know it has to be from n=4 to n=15

OpenStudy (perl):

$$ \large \sum_{n=4}^{15}a_n $$

OpenStudy (perl):

which of those a_n gives you (1,5) (2,-10) (3,20)

OpenStudy (anonymous):

Arent those the first 3 terms that they give me in the box? i think its a but im not sure a is 5(-2)^n-1

OpenStudy (anonymous):

@perl

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