Mathematics
11 Online
OpenStudy (anonymous):
4. Evaluate 10∑n=2 25(0.3)^n-1
5. Given the sequence in the table below, determine the sigma notation of the sum for term 4 through term 15.
n a^n
1 5
2 -10
3 20
11 years ago
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OpenStudy (anonymous):
@madmoiselle_sarcasm
@Agl202 @madmoiselle_sarcasm
11 years ago
OpenStudy (anonymous):
Sorry not doing that math yet.
11 years ago
OpenStudy (anonymous):
Oh dear my future ahhh
11 years ago
OpenStudy (anonymous):
@madmoiselle_sarcasm lol thanks anyways
11 years ago
OpenStudy (anonymous):
@math
11 years ago
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OpenStudy (anonymous):
You're welcome :)
11 years ago
OpenStudy (anonymous):
@mickyboy0202 @Mendicant_Bias @TheEdwardsFamily @logan420 @DiamondBear3299
11 years ago
OpenStudy (minecraft40952):
ummm sorry i dont know this im still in pre algebra
11 years ago
OpenStudy (anonymous):
aww, thanks anyways lol
11 years ago
OpenStudy (anonymous):
id like step by step help , because the lesson doent have an example for these 2
11 years ago
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OpenStudy (anonymous):
@perl can you help me?
11 years ago
OpenStudy (perl):
im having trouble reading your question
11 years ago
OpenStudy (anonymous):
is it the way i typed it?
11 years ago
OpenStudy (perl):
Is this the question?
$$
\Large \sum_{n=2}^{10} n $$
11 years ago
OpenStudy (anonymous):
yes~ and right next to it is 25(0.3)^n+1
11 years ago
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OpenStudy (perl):
$$
\Large \sum_{n=2}^{10} n= 2 + 3 + 4 + 5+ 6 + 8 + 9 + 10
$$
11 years ago
OpenStudy (anonymous):
=47
But the question is this exactly
∑n=210n 25(0.3)^n+1
11 years ago
OpenStudy (anonymous):
@perl ?
11 years ago
OpenStudy (perl):
yes
11 years ago
OpenStudy (perl):
can you take a screenshot of the assignment, or upload it
11 years ago
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OpenStudy (anonymous):
ok
11 years ago
OpenStudy (anonymous):
11 years ago
OpenStudy (anonymous):
11 years ago
OpenStudy (perl):
thanks
11 years ago
OpenStudy (perl):
$$
\large \sum_{n=2}^{10}25 (0.3)^{n+1} = 0.96426673425
$$
11 years ago
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OpenStudy (anonymous):
would you mind telling me how you got that answer?
11 years ago
OpenStudy (perl):
copy and paste that link
11 years ago
OpenStudy (anonymous):
how bout number 5?
11 years ago
OpenStudy (anonymous):
anks on number 4 really appreciated :)
11 years ago
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OpenStudy (anonymous):
and thanks *
11 years ago
OpenStudy (anonymous):
@perl are you still there? lol
11 years ago
OpenStudy (perl):
one moment be right back
11 years ago
OpenStudy (anonymous):
ok
11 years ago
OpenStudy (perl):
we know it has to be from n=4 to n=15
11 years ago
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OpenStudy (perl):
$$
\large \sum_{n=4}^{15}a_n
$$
11 years ago
OpenStudy (perl):
which of those a_n gives you (1,5) (2,-10) (3,20)
11 years ago
OpenStudy (anonymous):
Arent those the first 3 terms that they give me in the box?
i think its a but im not sure
a is 5(-2)^n-1
11 years ago
OpenStudy (anonymous):
@perl
11 years ago