A water balloon is tossed into the air with an upward velocity of 25 ft/s. Its height h(t) in ft after t seconds is given by the function h(t) = − 16t2 + 25t + 3. Show your work.
19. After how many seconds will the balloon hit the ground? (hint: Use the quadratic formula)

Question

A water balloon is tossed into the air with an upward velocity of 25 ft/s. Its height h(t) in ft after t seconds is given by the function h(t) = − 16t2 + 25t + 3. Show your work.  
  19.  After how many seconds will the balloon hit the ground?  (hint:  Use the quadratic formula)

solomonzelman · Answer

the balloon will hit the ground when h(t)=0, so we need to set h(t)=0 and solve for t.

solomonzelman · Answer

$\large\color{royalblue}{   0= - 16t^2 + 25t + 3                 }$    Now, solve for $\large\color{royalblue}{   t          }$.

anonymous · Answer

i don't know how to do it

solomonzelman · Answer

Use the quadratic formula. Here I will give you something:
$\normalsize\color{ slate }{\Huge{\bbox[5pt, lightcyan ,border:2px solid  black  ]{  \LARGE{x=~} \huge{  \frac{-\color{magenta}{b} \pm\sqrt{ \color{magenta}{b} ^2-4 \color{blue}{a} \color{red}{c}}}{2 \color{blue}{a}} }~ }}}$

when the equation is   $\LARGE\color{black}{  \color{blue}{a} x^2+ \color{magenta}{b}x+ \color{red}{c}=0  }$.

solomonzelman · Answer

Try to find your "a" "b" and "c".

solomonzelman · Answer

$\LARGE\color{black}{  \color{blue}{-16} x^2+ \color{magenta}{25}x+ \color{red}{3}=0  }$
hope this is better.

anonymous · Answer

what I need to next

solomonzelman · Answer

paste the numbers into the quadratic formula, and solve for x.

anonymous · Answer

i'm not sure how I have  5 more question that they are the same as this

anonymous · Answer

can u help me just with this please

solomonzelman · Answer

|dw:1425346835484:dw|