Question

Is this correct so far?
8^(-4x-5)=4^(2x-0
=ln 8^(-4x-5)= ln 4^(2x-0)
=(-4x-5) * ln 8 = (2x-0) * ln 4
=(-4x-5) / (2x-0) = ln 4/ ln 8...

Answer 1

\(\large\color{slate}{ 8^{-4x-5}=4^{2x-0} }\) is this the problem ?

Answer 2

yes, but the second exponent should be 2x-1

Answer 3

here, how I would start.

\(\large\color{slate}{ \left( 8\right)^{-4x-5}=\left( 4\right)^{2x-1} }\)

\(\large\color{slate}{ \left( 2^{3}\right)^{-4x-5}=\left( 2^{2}\right)^{2x-1} }\)

\(\large\color{slate}{ \left( 2\right)^{3(-4x-5)}=\left( 2\right)^{2(2x-1)} }\)

Answer 4

then you don't need to use any logarithms.

Answer 5

(and of course, then equation the exponents and solve for x ... ) hope this is helpful

Answer 6

as in now I should only need 3(-4x-5) = 2(2x-1)
into -12x-15=4x-2
into x=13/3?

Answer 7

x= -13/3

Answer 8

-12x-15=4x-2
-15=16x-2
-13=16x
x=-13/16

Answer 9

like this

Answer 10

sorry ....stupid mistake on my part. I greatly appreciate you taking the time to help me. Thank you