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Mathematics 7 Online
OpenStudy (anonymous):

Calculate the slant height for the given cone. Round to the nearest tenth.

OpenStudy (anonymous):

OpenStudy (compassionate):

Do you know the formula for the height of a cone?

OpenStudy (anonymous):

Nope.. I'm completely lost ;_;

OpenStudy (e.mccormick):

Actually, it is slant height, so you can just look at the right triangle there. Know your triangle formulas?

OpenStudy (compassionate):

\[Height = 3\frac{ V }{ \pi r^2 }\] Where V = Volume pi = 3.14 And radii = 4 (Since the diameter is 8, and radius = diameter/2)

OpenStudy (mathstudent55):

You need the Pythagorean theorem.

OpenStudy (e.mccormick):

Comp, what does that have to do with slant height?

OpenStudy (compassionate):

Whoops. I misread your question. Slant Height is different.

OpenStudy (anonymous):

I'm so confused ._.

OpenStudy (e.mccormick):

Yep. The Pythagorean Theorem. Just be careful with the leg lengths. They made one number a tad bit tricky.

OpenStudy (mathstudent55):

|dw:1425337661251:dw|

OpenStudy (e.mccormick):

Sam, just forget what Comp typed in at first... they were thinking about height and volume, not the slant height. Jist look at the pic math student drew.

OpenStudy (mathstudent55):

The slant height is the hypotenuse of a right triangle. You know the lengths of the legs. One leg is the height of the cone, and the other leg is the radius of the cone, which is half the diameter.

OpenStudy (compassionate):

Well, you could assume by rearranging the Pythagorean theorum that \[SH = \sqrt{r^2 + h^2}\]

OpenStudy (anonymous):

??! Am I overthinking this or...?

OpenStudy (e.mccormick):

Well, know your Pythag? \(a^2+b^2=c^2\)?

OpenStudy (e.mccormick):

For any right triangle, the square of the hypotenuse is equal to the sum of the squares of the legs. |dw:1425338206567:dw| \(a^2+b^2=c^2\)

OpenStudy (e.mccormick):

As you can see, that can be applied to this problem to make the drawing mathstudent55 did: |dw:1425338305132:dw|

OpenStudy (anonymous):

So, what do I do? {math especially angles and triangles and all that fun stuff I can never figure out}

OpenStudy (e.mccormick):

Well, what is your height from your diagram?

OpenStudy (anonymous):

9 cm

OpenStudy (e.mccormick):

Good. Now, what is your base leg lenth?

OpenStudy (anonymous):

8 cm..?

OpenStudy (e.mccormick):

Not quite. It is related to that, but that is the diameter. You want just the radius.

OpenStudy (anonymous):

oh 4

OpenStudy (e.mccormick):

Good! |dw:1425338765680:dw| OK, so, put those into the formula.

OpenStudy (anonymous):

Umm..

OpenStudy (anonymous):

like 9^2 + 4^2?

OpenStudy (e.mccormick):

YES!

OpenStudy (e.mccormick):

What you get will be the square of the hypotenuse, or the square of the slant height. So all that is left after squaring and adding is finding the root.

OpenStudy (anonymous):

wait so like 81 + 16 = 97 then you find the root?

OpenStudy (e.mccormick):

Yes. That is it. \(\sqrt{97}\) will be it.

OpenStudy (anonymous):

What do you do to get the square root again?

OpenStudy (e.mccormick):

Well, it says to round to the nearest 10th. So I would use a calculator and round off.

OpenStudy (anonymous):

ok thanks

OpenStudy (anonymous):

so 10.2 ??

OpenStudy (anonymous):

@e.mccormick

OpenStudy (anonymous):

actually 9.8

OpenStudy (e.mccormick):

10*10 = 100, so 10^2 would be too high. 9^2=81, so too low. It will be some number between 9 and 10.

OpenStudy (anonymous):

Can I tag you in a couple more questions? It shouldn't take as long..

OpenStudy (e.mccormick):

Yah, 9.8 is to the nearest 10th.

OpenStudy (e.mccormick):

Well, I am getting some fun reports to deal with at the moment...

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