1. In each of the following cases, determine whether the variable of interest has a binomial distribution. If it does, give the values of the parameters n and p. If it doesn't, explain why not. (a) You are dealt a five-card poker hand. X = the number of Diamonds in your hand. (b) You randomly select one card from each of ten different decks of playing cards. X = number of Clubs selected.
(c) Heights of females in some population follow a normal distribution with a mean of 65 inches and standard deviation of 1.5 inches. We take a random sample of three women. X = number of women in the sample shorter than 64 inches. (d) A boy asks the same girl to go out on a date every day for a week. X = the number of times the girl agrees to go on the date. (e) A multiple choice exam has 30 questions with choices (A, B, C, D and E). An unprepared student guess all of the answers. X = the number of answers he gets correct.
Do you have the notes to describe the conditions under which binomial distribution applies? There are several criteria, all of which must be satisfied. We cannot go by guess work. @AprilZ
@AprilZ You still need help?
Yes. @mathmate Binominal Setting: 1.The experiment consits of a sequence of n trails, where n is fixed in advance of the experiment. 2) There are only two possible outcomes for each trial (a success or a failure). 3) The trials are independent, so that the outcome of any particular trial does not influence the outcome of any other trial. 4) The probability p of a success is constant from trial to trial. An experiment for which these four conditions are satisfied is called a binomial experiment.
Excellent! Now you can examine each case, give your verdict, and I can help you if necessary.
@mathmate (a)no it is not binomial distribution. Because n is not defined. (b) n = 10 p = 0.25 (c) n = 3 p = probability of shorter than 64 inches. (d) It is not binomial distribution. It is not independent. (e) n = 30 p = 0.2 This is all my answers, but I'm not sure whether they are correct. Could you help me to take a look at them please. Thank you!!
(a) n = 5 is given. Can you reconsider? (b) is correct
(c) n=3, and p has to be determined from theNormal distribution table for \Z=-2/3
(d) exactly, \(normally\) each trial is not independent due to emotions.
(e) is perfect! Cool, you seem to have a good handle of things!
so what is p for (a)?
p is variable, depending on how many diamonds have been given out at each point.
ok! Thanks for your help!!
You're welcome, April! :)
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