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Rewrite with only sin x and cos x. cos 2x - sin x
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@jim_thompson5910
Is this $$ \cos^2x-\sin x\\ or\\ \cos 2x-\sin x $$ ?
the second
of which you provided
So, $$ \cos 2x=\cos^2x-\sin^2x $$ Combine this with \(\sin x\)
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not sure how thats why im here
$$ \cos 2x-\sin x\\ =\cos^2x-\sin^2x-\sin x $$ Make sense?
yep simply multiplied each side by sin x
No. I found \(\cos 2x\) in terms of \(\cos x\) and \(\sin x\) and then added to \(\sin x\), which is already in the form we desire.
alright, so the next step?
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