Circle D circumscribes ABC and ABE. Which statements about the triangles are true? Statement I: The perpendicular bisectors of ABC intersect at the same point as those of ABE. Statement II: The distance from C to D is the same as the distance from D to E. Statement III: bisects CDE. Statement IV: The angle bisectors of ABC intersect at the same point as those of ABE.
I think Statement IV
well, statement 2 is obviously true, because CD and DE are radii, and thus they are equal in length
maybe correct Rizgas
statement 3 is incomplete, there is no first term
by the way, if it helps at all, triangles ABC and ABE are right triangles because their vertices lay on the circumference of the circle, and their hypotenuse is the diameter
@Rizags That's what I thought too!!!
Duh?
i need a completion of statement 3 to finish
statement 1 is true, because the perpendicular bisectors must all meet at point D, because considering each side of the triangle as a chord, a line segment can be drawn from the center of a circle to any chord, such that the segment bisects AND is perpendicular to the chord
statement 4 cannot be true. i do not know how to formally prove it, but visually it is impossible
so yea, gimme statement 3!!
1 only 1 and 2 2 and 4 1 and 3 3 and 4
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