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Mathematics 19 Online
OpenStudy (nightmarenight):

Can someone check my answers? I'm not sure I have them all right. Will fan and give a medal for help! attached below

OpenStudy (nightmarenight):

What is the y-intercept of the plane whose equation is 4x + 5y z = 20? (0, 4, 0) < my answer (0, 5, 0) (5, 0, 0) (0, 0, 4) Question 2. Which equation has intercepts at X(1, 0, 0), Y(0, 1, 0), and Z(0, 0, 2)? x y + 2z = 4 3x 2y + 6z = 12 2x 2y + z = 2 4x 4y + z = 4 Question 3. Which equation is equivalent to x + 3y z = 3? 3x + 6y 3z = 6 4x + 12y 4z = 12 2x + 4y 2z = 8 2x + 3y 4z = 12 Question 4.4. Which of the following points lies in the plane 3x 2y + 4z = 12? (2, 2, 3) (5, 15, 2) (4, 16, 2) < my answer (4, 3,2)

OpenStudy (nightmarenight):

@perl

jimthompson5910 (jim_thompson5910):

4x + 5y z = 20 seems to have a typo?

OpenStudy (nightmarenight):

@jim_thompson5910 the first one?

jimthompson5910 (jim_thompson5910):

yeah, there are others where it seems like there's a missing symbol

OpenStudy (nightmarenight):

What is the y-intercept of the plane whose equation is 4x + 5y - z = 20?

jimthompson5910 (jim_thompson5910):

So you plug x = 0 and z = 0 4x + 5y - z = 20 4*0 + 5y - 0 = 20 5y = 20 y = 4 so yeah it is (0,4,0)

OpenStudy (nightmarenight):

I see it now, it's just a - symbol Which equation has intercepts at X(1, 0, 0), Y(0, -1, 0), and Z(0, 0, 2)?

OpenStudy (nightmarenight):

that #2^^^

OpenStudy (nightmarenight):

Can you help me out with the others because I don't know them

jimthompson5910 (jim_thompson5910):

can you post the updated choices for #2. They are missing symbols

OpenStudy (nightmarenight):

x - y + 2z = 4 3x - 2y + 6z = 12 2x - 2y + z = 2 4x - 4y + z = 4

jimthompson5910 (jim_thompson5910):

here is one way to do it: we're given a list of choices, so why not use them to check each point For instance, choice A is x - y + 2z = 4 if choice A was the answer, then (1,0,0) must be on this plane. Let's check that claim x - y + 2z = 4 1 - 0 + 2*0 = 4 ... plug in (x,y,z) = (1,0,0) 1 - 0 + 0 = 4 1 = 4 ... this false, so (1,0,0) is NOT on the plane. This cannot be the answer so choice A is out.

jimthompson5910 (jim_thompson5910):

do you see how I was able to eliminate choice A?

OpenStudy (nightmarenight):

oh yea I do

OpenStudy (nightmarenight):

I think it might be C

jimthompson5910 (jim_thompson5910):

you have to make sure ALL 3 points make the equation true

jimthompson5910 (jim_thompson5910):

Let's check that

jimthompson5910 (jim_thompson5910):

Checking (1,0,0) 2x - 2y + z = 2 2*1 - 2*0 + 0 = 2 2 = 2 ... works ------------------------------------------------------- Checking (0, -1, 0) 2x - 2y + z = 2 2*0 - 2*(-1) + 0 = 2 2 = 2 ... works ------------------------------------------------------- Checking (0, 0, 2) 2x - 2y + z = 2 2*0 - 2*0 + 2 = 2 2 = 2 ... works

jimthompson5910 (jim_thompson5910):

since all 3 points make the equation 2x - 2y + z = 2 true, we've confirmed the answer

OpenStudy (nightmarenight):

So I was right it is C? :)

OpenStudy (nightmarenight):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

yes and I show how it's true

OpenStudy (nightmarenight):

Can you help me with 3? @jim_thompson5910 Which equation is equivalent to x + 3y - z = 3? 3x + 6y - 3z = 6 4x + 12y - 4z = 12 2x + 4y - 2z = 8 2x + 3y - 4z = 12

jimthompson5910 (jim_thompson5910):

We see '3' on the right side of the original equation. Look at choice A. Notice how there is a 6 on the right side. What happened going from 3 to 6?

jimthompson5910 (jim_thompson5910):

hint: multiplication

OpenStudy (nightmarenight):

Hmmm @jim_thompson5910 is it B?

jimthompson5910 (jim_thompson5910):

do you see what I'm asking?

OpenStudy (nightmarenight):

not sure

jimthompson5910 (jim_thompson5910):

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