Question

NEED HELP PLEASE!!! I WILL MEDAL!!

Answer 1

If m = 8 in and n = 10 in, what is the surface area of the geometric shape formed by this net?
128 sq in
208 sq in
224 sq in
https://app107.studyisland.com/pics/268427pic3.png

Answer 2

area of the square = 8^2
area of each triangle = 1/2 * base * height = 1/2 * 8 * 10

Answer 3

total rea = area square + 4* area of triangle

Answer 4

so that means? sorry im not good at this

Answer 5

can you work out the area of the square and of one of the traingles
calculate them from the formula i giave you in my furst post

Answer 6

how?

Answer 7

8^2 = ?
1/2 *8*10 = ?

Answer 8

8^2 = 8*8 = ?

Answer 9

8 times 8

Answer 10

1,024

Answer 11

??? 8*8 = 1024?

Answer 12

oh 8 times 8 = 64

Answer 13

That's makes a triangular prism..

Answer 14

right
now the area of a triangle = half of the base times the height
= half of 8 times 10
can you compute that?

Answer 15

half of 80 is 40 so 40?

Answer 16

A square pyramid to be exact.

\(SA_{Square~Pyramid} = s^2 + 2 \times s \times l\)

Where 's' is the side length, and 'l' is the slant height.

Here, 'm' is the side length, and 'n' is the slant height.

Plug in what we know:

\(SA_{Square~Pyramid} = 8^2 + 2 \times 8 \times 10\)

Simlpify

Answer 17

*Simplify

Answer 18

yes
now the total area of the net is the area of the square + area of the triangles
there are 4 triangles
so total area = 64 + 4 times 40 = ?

Answer 19

Lol

Answer 20

:( it exited out it does that when you take 2 long 2 answer

Answer 21

Oh..

Answer 22

work out the area of the 4 triangles first
this is 4*40
then add the area of the square (64 )