Can someone help me graph this polar equation?

Question

anonymous · Answer

r = 1 + 2 cos θ.

anonymous · Answer

r = 1 + 2 cos(theta)

irishboy123 · Answer

if it was just r = cos(theta), what would it be?!?!

anonymous · Answer

Like a semi circle or something

michele_laino · Answer

please try this substitution:
$$\begin{gathered}
  x = r\cos \theta  \hfill \
  y = r\sin \theta  \hfill \
  {x^2} + {y^2} = {r^2} \hfill \ 
\end{gathered} $$

michele_laino · Answer

for example if we have:
$$r = \cos \theta $$
then using that above substitution, we get:
$$\begin{gathered}
  {r^2} = x \hfill \
  {x^2} + {y^2} = x \hfill \
  {x^2} + {y^2} - x = 0 \hfill \ 
\end{gathered} $$
which is the equation of a circumference

michele_laino · Answer

oops...missing step:
$$r = \frac{x}{r}$$

michele_laino · Answer

now, please do the same with your equation:
$$r = 1 + 2\cos \theta $$

igreen · Answer

https://www.desmos.com/calculator/tq0cv7ika7

igreen · Answer

Is that what you wanted? @swagmaster47

irishboy123 · Answer

i had assumed he wanted to graph it himself, in which case i would not go about converting to cart.  rather, i'd try get a sense for what it might look like the take π/4 steps and have a crack at drawing it....