Question

help me please
a rocket is released a jet fighter flying horizontally at 1200 kph at an altitude of 2400 m above its target. The rocket thrust gives it a constant horizontal acceleration a = 0.6 g. Determine the angle between the horizontal and the line of sight to the target. help me pleaseeeeeeeeeeeeeee

Answer 1

ok you have horizontal acceleration, but the same vertical acceleration of g (normal gravity acceleration)

Answer 2

okay i hVE the drawing

Answer 3

we can approach this using calculus

Answer 4

wait i will draw it can i

Answer 5

$$
\\ \Large x ' ' (t) = 0.6g = 0.6 (9.81) \frac{m}{s^2}
\\ \Large
\\ \Large
\\ \Large
\\ \Large
\\ \Large
\\ \Large
\\ \Large

$$

Answer 6

sure go ahead , i will continue , i have a lot of equations to write

Answer 7

here