Solve the system of linear equations and check any solution algebraically. x + y + z = 2 -x + 3y + 2z = 8 4x + y = 4
do you know how to use the elimination method? probably, what we can do is to eliminate z variable first using the 1st and 2nd equation then use the resulting equation apply another elimination method to solve for the variable x or y ^_^ so first, what can you do to the 1st and 2nd equation to eliminate z?
So could we multiply the 1st equation by 2 and then subtract it from the 2nd equasion?
yes exactly :)
i'm trying to solve it... just tell me what equation you'll get after you applied what you said and let's compare it to mine, sounds good?
ok, so after multiplying and subtracting you would get x + y + z = 2 3x - y = 8 4x + y = 4 right?
wait, you should do what you said: \(\color{blue}{\text{Originally Posted by}}\) @alyssajobug So could we multiply the 1st equation by 2 and then subtract it from the 2nd equasion? \(\color{blue}{\text{End of Quote}}\) multiply 1st equation by 2 : so it will be 2x+2y+2z=2 then subtract this by 2nd equation
you should end up with one equation (leave equation 3 for now)
So x + y + z = 2 3x - y =4 4x + y = 4 ?
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