Please Help!
with what?
Tag me once you get your question posted @sammixboo =)
Evaluate. |dw:1425428363402:dw|
First subtract 3 - 9, which is?
-6?
yes
okay.
Yup! So now we have |dw:1425428677048:dw|
Now we do what's in the other parenthesis, 8 - 2, which is?
6.
Right! so now we have \(\dfrac{6(5\times-6 - 1)+2}{7\times6+4}\) Now still doing what's in the parenthesis, what is \(5\times-6 - 1\)
Wait a minute, I think there's a problem with the way I wrote it.
One moment, please! :)
Okie dokie! Tag me when you finish
|dw:1425428918696:dw| This is what it is, on the problem, how it's written COULD make a difference.
@sammixboo
Yeah, it's the same way you wrote it above, hehe. Brackets [....] is the same as parenthesis (....)
Okay, but the question that's bothering me is the in first equation. Is the 1 in the equation negative?
@sammixboo
No, it's subtracting 1, anyways, let's continue. We have this \(\dfrac{6(5\times-6 - 1)+2}{7\times6+4}\) Still working in the parenthesis, what is \(5\times-6 - 1\)? First multiply 5 and -6 then subtract 1
-31
Right! so now we have \(\dfrac{6\times-31+2}{7\times6+4}\) Now let's do all that multiplication in that problem. What is 6 times -31 and 7 times 6
first one is -186 and the other one is, 42.
Right! So now we have \(\dfrac{-184+2}{42+4}\) What's -184 + 2 and 42 + 4?
I meant -186
Not -184, sorry
XD you just gave me the answer! First one is -184, and the other is 46
@sammixboo
Whoopsie xP
Yes! Now divide -184/46
goshdarnit! My original answer was so close yet so far! >:/ but anyway the answer is...four.
My original answer was 4.04 :/
I guess you could say, I made an ERROR Hahahaha!
@sammixboo
Hehe, anyways, the answer isn't 4. WHen dividing a negative by a positive, the answer will always be negative, so it's -4 :)
oh right I got negative four sorry. I completely cut off the negative sign.
@sammixboo I could still use your help though.
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