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Algebra 7 Online
OpenStudy (anonymous):

y=1/2√x find the domain Help please

OpenStudy (anonymous):

i am pretty sure it is 0 to infinity

OpenStudy (anonymous):

actually im positive.

OpenStudy (anonymous):

thanks but its different problems similar to this i need to know how to do it for example y=3√x/3

OpenStudy (anonymous):

not sure what is up with all the question marks but is the equation y=3x/3 ?? if so the 3's would cancel and you are left with y=x and the domain is -infinity to +infinity

OpenStudy (anonymous):

oh and no it has a square root in the problem

OpenStudy (mathmate):

y=3√(x/3) ?

OpenStudy (mathmate):

@teetee4455 or \(3\sqrt{\dfrac{x}{3}} ?\)

OpenStudy (anonymous):

@mathmate was just about to ask that or is it sqrt(x)/3

OpenStudy (anonymous):

yes i didnt know how to make that sign @mathmate

OpenStudy (anonymous):

then it is 0 to positive infinity

OpenStudy (mathmate):

In both cases, the domain is limited by the square-root sign. The content of the square-root radical must not be negative, or else the result will be complex (or imaginary). For that not to happen, x must be greater than zero, which makes dom [0,inf).

OpenStudy (anonymous):

basically what @mathmate said. in your head plug in numbers starting at 0 for x and then divide by 3 and multiply that by the outside 3. it has to be 0 or greater otherwise you have to deal with i which is imaginary

OpenStudy (anonymous):

I understand thanks to the both of you much help @mathmate @clickspiker23

OpenStudy (mathmate):

you're welcome, Teetee! :)

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