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Algebra 9 Online
OpenStudy (anonymous):

Factor. Use factoring by grouping even though it would seem reasonable to first combine like terms. 2s2−7s−14s+49 @Nnesha

OpenStudy (anonymous):

I got 2s( s+7) (2s^2+7)

OpenStudy (mathmate):

If you multiply it out, you will find that the expression is not the same as the given question. Grouping consists of putting together terms that have similar ratios, for example: 2s2−7s−14s+49 we put together (2s^2-14s) +(-7s+49) they two groups both have a factor of 7, so we can take out the common factor of each group: 2s(s-7) + -7(s-7) Now we see that (s-7) is a common factor, means we succeeded in grouping. The next step is to extract the common factor (s-7) to get (s-7)(2s-7) as the final factorization.

OpenStudy (anonymous):

so the answer will be (2s-7)

OpenStudy (anonymous):

why would the answer not be (s-7)(2s-7)?

OpenStudy (anonymous):

just for future knowledge i am confused with why this (2s-7) would be the only answer.

OpenStudy (anonymous):

@dontre

OpenStudy (mathmate):

@dontre The answer will be (s-7)(2s-7) or (2s-7)(s-7) because you are asked to factor. @huntergirl1 you're right the answer should contain both factors.

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