Question

will medalllll help

The function f(x) = 467(5)x represents the growth of a ladybug population every year in a wooded area. Adrianne wants to manipulate the formula to an equivalent form that calculates every 3 months, not every year. Which function is correct for Adrianne's purposes?

f(x) = 67(5)^x

f(x) = 467(5^12)^x/12

f(x) = 467(5^1/4)^4x

f(x) = 4672(5)^x

Answer 1

\[f(x)=67(5)^{x}\]
\[f(x)=467(5^{12})^{x/12}\]
\[f(x)=467(5^{1/4})^{4x}\]
\[f(x)=4672(5)^{x}\]

Answer 2

\(

f(x) = 67(5)^x
\\
f(x) = 467(5^{12})^{\frac{x}{12}}
\\
f(x) = 467(5^{\frac{1}{4}})^{4x}
\\
f(x) = 4672(5)^x
\)
is that it? oh you rewrote it yourself

Answer 3

HI!!

Answer 4

are those possible answer choices?

Answer 5

Yes they are

Answer 6

that is what i thought

Answer 7

every three months is one quarter of a year

Answer 8

So then it would be C?

Answer 9

the number in front does not change

Answer 10

yeah as always it is C

Answer 11

Thank you :)