Question

A right cicular cylindrcal tank of height 10 ft and radius 5 ft is lying horizontally and is full of diesel fuel weighing 53 lb/ft^3. How much work is required to pump all of the fuel to a point 15ft abouve the top of the tank?

Answer 1

would you like help with this

Answer 2

Yeah, I don't get these question about work and fluid forces.

Answer 3

you can divide the tank into thin slabs which have weight
weight density * volume
= weight density * area of circle * thickness

Answer 4

53pi(r)^2deltaY ?

Answer 5

I will have to draw a picture, but my draw button is dead

Answer 6

be right back *

Answer 7

okay!

Answer 8

Alright

Answer 9

each thin circular slab has the same weight of :
weight density * volume.

this is because weight density is weight per unit volume, times volume , makes weight.

Now the volume of the i'th slab is pi * r^2 * delta y.

Work = force * distance.
here the force is weight, but the distance varies, the bottom slabs have to travel further than the top slabs. that is why we need to integrate . The distance

Work = weight density *(pi * r^2 * delta y) *( distance i'th slab travels)

IF we set the tank at the origin, the distance from the origin to the slab is y, and the height it has to travel is (15 - y)