Question

Will give medals. *PICTURES ATTACHED*

Answer 1

Answer choices...

Answer 2

for starters, find the x intercept by setting y = 0

Answer 3

isn't it already set to y = ?

Answer 4

replace y with 0 to find the x-intercept

Answer 5

aka solve for x where \(0=\sqrt[3]{x-5}-1\)

Answer 6

0 = ^3sqrt x - 5 - 1

Answer 7

Would I add 5 to 1 and then divide by 3?

Answer 8

whoops, was tabbed out
add 1 first, you can't add 5 because it's under the root/radical

Answer 9

Ok so it would be ^3sqrt x - 6

Answer 10

How would I graph it?

Answer 11

nope, think of them as 2 separate entities
\(0=\sqrt[3]{\color{green}{x-5}}-\color{red}1\)

Answer 12

so first we add 1 to both sides
\(1=\sqrt[3]{x-5}\)

then we continue solving for x

Answer 13

right now we're trying to find the point where that equation hits the x axis so we can eliminate the wrong choices

Answer 14

also worth referencing: http://www.wolframalpha.com/input/?i=y%3Dcube+root+%28x-5%29+-1

what happens is \(y=\sqrt[3]{x-5}-1\) is \(f(x-5)-1\) where f(x) = \(\sqrt[3]{x}\)

what that means is that our graph is the same graph as \(\sqrt[3]{x}\), but moved down 1, and to the right 5

Answer 15

So would that be the the second graph?

Answer 16

yeah

Answer 17

Thank you for your help!

Answer 18

np yo