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Mathematics 10 Online
OpenStudy (anonymous):

Is this function continuous? lim(x,y)->(-3,3) e^(-xy)(cos(x+y))

OpenStudy (anonymous):

\[\lim_{(x,y) \rightarrow (-3,3)} e^{-xy}\cos (x+y)\] For a better view!

OpenStudy (xapproachesinfinity):

well cos is a cont function so is exp function what the is the problem

OpenStudy (xapproachesinfinity):

just evaluating the limit?

OpenStudy (anonymous):

Yes! But don't I have to determine continuity before I can plug in the values? If it's not continuous, I have to take the partial derivative, right?

OpenStudy (anonymous):

In this case, I'm allowed to just plug it in since it's a continuous function?

OpenStudy (xapproachesinfinity):

there is really nothing to determine cos is a continues function R^2 to R^2 so is exp

OpenStudy (xapproachesinfinity):

just evaluate the limit

OpenStudy (anonymous):

Thank you!

OpenStudy (xapproachesinfinity):

welcome

OpenStudy (anonymous):

It's Calc 3!

OpenStudy (xapproachesinfinity):

why did you delete the comment lol i was trying to make sense of it

OpenStudy (xapproachesinfinity):

i believe it is continuous i took into account that we are dealing with multivariable calc of course

OpenStudy (xapproachesinfinity):

All the standard functions that we know to be continuous are still continuous even if we are plugging in more than one variable now. We just need to watch out for division by zero, square roots of negative numbers, logarithms of zero or negative numbers, etc. ==== see this

OpenStudy (thomas5267):

Both function are differentiable throughout R^2 so it is continuous?

OpenStudy (zzr0ck3r):

cos is not a function from R^2 to R^2 @xapproachesinfinity

OpenStudy (zzr0ck3r):

differentiable implies continuity yes, but not the other way around (exp |x|)

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