Question

Find dy/dx.
2x^2y^2=x^3+y^3

Answer 1

\[(2x^2y^2)\prime=(2x^2)(y^2)\prime+(2x^2)\prime(y^2)\]

Answer 2

@esam2 can u calculate this ?^

Answer 3

i'm not that good at this...

Answer 4

\[(y^2)'=?\]

Answer 5

2y

Answer 6

2yy'

Answer 7

\[(2x^2)'=?\]

Answer 8

4x

Answer 9

true

Answer 10

now can u differentiate right side?

Answer 11

this is Implicit Functions

Answer 12

I'm very new to this concept, i need some help

Answer 13

\[(x^3)'= ? \]
\[(y^3)'=?\]

Answer 14

3x
3y^2 y'?

Answer 15

correct . but \[(x^3)'=3x^2\]

Answer 16

oh oops

Answer 17

\[(2x^2y^2)'=(x^3)'+(y^3)'\]
\[(2x^2)(2yy')+(4x)(y^2)=(3x^2)+(3y^2y')\]

Answer 18

now find y'

Answer 19

\[\frac{ 3x^2-4xy^2 }{ 4x^2y-3y^2 }\]
???

Answer 20

correct :)

Answer 21

thank you! :)