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Help with solving real life problems with right triangles
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You are standing on a cliff that is 50 m above the ocean and you see a ship that is 950 m from the bottom of the cliff. Find the angle of depression from you to the ship. Round your answer to the nearest tenth of a degree.
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is that what it would look like?
tan=50/950?
yeah
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0.0526?
well... \(\tan(\theta)=\dfrac{50}{950}\) So you need to find the angle by applying \(\tan^{-1}\) to both sides
So both to 50 and 950?
\[\theta=\tan^{-1}\left(\dfrac{50}{950}\right)\].. which you'd need to find on your calculator
3 degrees?
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Yeah. Although they say to the nearest tenth, so 3.0
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