find the value of x.
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first of all ignore the circle
then put an imaginary line where the 2 triangles meet
you will see that one of the triangles is just a reflection
because they are a reflection x=40 degrees
@jacobrocket173buuuttt.....we've to use the circle to solve that....any proof?
but still picture a line that cuts everything in half
then fold where you made the line and angle x should equal the angle with 40 degrees
an inscribed angle equals 1/2 of the intercepted arc. notice that both "inscribed angles" have the *same intercepted arc* same arc means same inscribed angle.
im just soo use to the triangles by its self okay so sry if the info i gave is wrong
so wait am i half right or completely wrong
@jacobrocket173 you are correct that x is 40 degrees, but you should not assume the triangles *appear* to be reflections of each other... they are, but to prove it, you should use a geometric theorem (such as the one about inscribed angles)
remember im being taught differently okay
i can prove it use a diff theorem tho if i had another angle
@jacobrocket173 thanks for the answer anyway.....atleast you tried!
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