Question

A sample of methane that initially occupies a 850.0 mL at 500.0 kPa and 500.0K is compressed to a volume of 7000.0mL. To what temperature will a gas need to be cooled to lower the pressure of gas to 200.0 kPa

Answer 1

@Somy COuld you possibly help real quick

Answer 2

sure
\[\sf \frac{ P_1V_1 }{ T_1 } = \frac{ P_2V_2 }{ T_2 }\]
\(\sf P_1\) = 500.0 kPa \(\sf \color{red}{convert ~ to ~ Pa}\)
\(\sf V_1\) = 850.0 mL \(\sf \color{red}{convert~ to ~m^3}\)
\(\sf T_1\) = 500.0K

\(\sf P_2\) = 200.0 kPa \(\sf \color{red}{convert ~ to ~ Pa}\)
\(\sf V_2\) = 7000.0mL \(\sf \color{red}{convert~ to ~m^3}\)

\(\sf T_2\) = ?

After converting values to proper units
Put them into formula and get the ans

Answer 3

Okay thanks

Answer 4

No problem :)