Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

Tina pet sits to earn extra money. She charges a flat service fee of $20, plus $20 per day. If one of her customers spent less than $140, which of the following inequalities could be used to solve for x, the number of days the customer paid for pet sitting? $20x + $20 < $140 $20x < $140 $20x - $20 < $140 $20x < $160

OpenStudy (anonymous):

@iGreen

OpenStudy (anonymous):

@kirbykirby he is great! he can help!

OpenStudy (kirbykirby):

Well the flat fee is 20, so that appears as a constant. Then, the 20 dollars per day... If \(x\) is the number of days, how do you think this part of the expression will look like? Without considering the 140$ for now. If it's 1 day: 20 + 20(1) 2 days: 20 + 20(2) .... 5 days: 20 + 20(5)

OpenStudy (anonymous):

So the answer is d?

OpenStudy (kirbykirby):

Um not quite. What do you think is the expression that shows how much was paid for pet sitting \(x\) amount of days? (Let's just look at that part without worrying about the 140$ part yet)

OpenStudy (anonymous):

B

OpenStudy (kirbykirby):

Well there is a 20 flat fee that is extra, that will always be added to the 20$ per day rate. So that extra 20 dollars has to be added extra to the 20x

OpenStudy (anonymous):

I am think between a and c.. ;-; Just so you know I am literately stupid.. ;-;

OpenStudy (anonymous):

So A

OpenStudy (kirbykirby):

Oh no don't say that :( Don't worry sometimes math can be hard sometimes. Just need to do lots of problems to grasp it well :) But yeah A would be good! 20 flat fee is added as extra to the 20x, so 20+20x , and all of that is less than 140$

OpenStudy (anonymous):

YAY THANK YOU SO MUCH! :')

OpenStudy (kirbykirby):

awesome =]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!