Question

In how many different orders can you line up 8 cards on a table? I'll FAN AND MEDAL!!!

Answer 1

@iGreen I think you use n!/(n-2)!

Answer 2

if all the cards are different and you arrange them in a straight line,

there are

8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 ways of arranging them.

There are 8 ways of choosing the first card, 7 ways of choosing the second (because once you've used a card you cannot choose it again)...and so on

I'll let you do the multiplying.....

Answer 3

40,320?

Answer 4

when do you use \[\frac{ n! }{ (n-r)! }\]

Answer 5

I'm so confused.. I know it's probably simpler than what I'm making it... I over think things all the time

Answer 6

YEs you are correct.

But @freegirl112 please make sure to cite your sources next time: https://sg.answers.yahoo.com/question/index?qid=20071217191209AAJa8MM

Answer 7

In most cases it looks like just this: 8!

Which is the same as 8*7*6*5*4*3*2*1

Answer 8

yeah sorry forgot to name the site thank you @Uanimoose

Answer 9

Okay...

Answer 10

thanks :)