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Mathematics 7 Online
OpenStudy (anonymous):

I will give a medal! Trigonometry

OpenStudy (anonymous):

OpenStudy (anonymous):

@shaydoe Can you help?

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

im not sure exactly sorry

OpenStudy (anonymous):

@zepdrix Can you help me?

myininaya (myininaya):

so we have f(x)=cos(x) and we know f(-x)=cos(-x)=cos(x) since cos(x) is an even function

myininaya (myininaya):

so you know f(x)=f(-x) for all x

myininaya (myininaya):

that means you know f(-a) since you are given f(a)

myininaya (myininaya):

for example cos(pi/4)=sqrt(2)/2 so cos(-pi/4) also equal sqrt(2)/2

myininaya (myininaya):

so if cos(a)=2/7 then cos(-a)=?

myininaya (myininaya):

well if you come back and I'm gone a hint for the second question is cos has period 2pi

OpenStudy (anonymous):

IM SO SORRY!!!!! @myininaya

OpenStudy (anonymous):

cos(-a)= 2/7 since it's an even function

myininaya (myininaya):

yep

OpenStudy (anonymous):

For the second one what's changing is the period? So (a+ 2pi) means having a period of 4pi?

OpenStudy (anonymous):

I'm confused

myininaya (myininaya):

do you know that cos(pi/4)=sqrt(2)/2 and that cos(pi/4+2pi)=sqrt(2)/2 and that cos(pi/4+4pi)=sqrt(2)/2 and that cos(pi/4+2npi)=sqrt(2)/2 where n is an integer

myininaya (myininaya):

so if cos(a)=2/7 then cos(a+2pi)=?

OpenStudy (anonymous):

2/7. ohhhh so its like a reference angle

myininaya (myininaya):

yeah and cos(a+4pi) still equals

myininaya (myininaya):

like it is like we are at a and go all the way around to get back to a so cos(a) is the same cos(a+2*pi*n) for an integer n

OpenStudy (anonymous):

2/7 + 2/7 + 2/7 = 6/7?

myininaya (myininaya):

yeah

OpenStudy (anonymous):

I understand what your saying. Thanks a lot :) youre the best

myininaya (myininaya):

:) np

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