Question

k

Answer 1

is a the base?

Answer 2

is that really
find \[\log_a(1)?\]
if so you don't need any of the info given
just that a>0 of course

Answer 3

\[\log_a(1)=\frac{\ln(1)}{\ln(a)}\]
and we know ln(1)=0

Answer 4

@myininaya why to do tht way
log 1 = 0
no matter whts the base........

Answer 5

\[\log_a(1)=0 \text{ as long as } a>0\]

Answer 6

wrote it like that just to make that part more clear if it wasn't already

Answer 7

@Directrix

Answer 8

*also I should also say a is an element of [0,1) U (1,inf)
to my above note


\[\log_a(9)=\log_a(3^2)=2 \cdot \log_a(3) \\ \text{ so we have } \\ \log_a(9)=2 \cdot \log_a(3) \\ \text{ divide both sides by } 2 \]

Answer 9

so whats the answer

Answer 10

that is the thingy you find by using what I have above for ya :)

Answer 11

ohh

Answer 12

you know what log_a(9) is

Answer 13

and to solve for log_a(3) you need to do that last step I asked you to do

Answer 14

log a 10?

Answer 15

oh I thought you were looking for log_a(3)

Answer 16

well hint: 20/2=10
use a division property for log

Answer 17

i get it