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If the point(x,3√3)is on the unit circle, what is x?
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on the unit circle, \[x ^{2} + y ^ {2} = 1\]
there are four answers
2/3 \[\sqrt{6}/3\] 4/9 \[\sqrt{2}/3\]
\[x^2+y^2 =1\] Now we have \[y=\frac{ \sqrt{3} }{ 3 }\]
those are my four options
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So then we plug this in \[x^2+(\frac{ \sqrt{3} }{ 3})^2=1\] Giving us \[x^2+\frac{ 3}{ 9 }= x^2+\frac{ 1 }{ 3}=1\]
i see what your saying but that isnt one of the given options
Thats because that's not the answer :), Solve for x And that should be your answer.
would it be \[\sqrt{2}/3\]?
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