Question

solve with boundary conditions ,

Answer 1

@texaschic101 can you come look at this need your help

Answer 2

There?

Answer 3

I am searching you here and there only.. :P

Answer 4

In both the cases, you just need to solve the equations and find out the variables..

Answer 5

\[a+b = -2 \\ 4a - 3b = 6\]

Answer 6

i have already solved it but iam having problems in finding the value of A and B

Answer 7

I am talking of solving \(a\) and \(b\)..

Answer 8

See, in our first equation: find out value of \(b\)..

Answer 9

For this, subtract \(a\) from both the sides:
\[a+ b-a = -2 -a \implies b = -2 - a\]
Good up to here?

Answer 10

yep

Answer 11

So, now put this value of \(b\) in second equation you are having, and you will find \(a\) then.

Answer 12

\[4a - 3 \color{red}{b} = 6 \\ 4a - 3\color{red}{(-2-a)} = 6 \\ 4a + 6 + 3a = 6 \\ 7a = 0 \implies \color{green}{a=0}\]

Answer 13

Wow..!!!, you got \(a=0\) and can you find \(b\) now??

Answer 14

yep b= -2

Answer 15

Good.. :)

Answer 16

\(\dagger\)..

Answer 17

i have one more question but i need it to be explained from the scratch

Answer 18

Did you get answer to your previous question? where you had A, B and C??

Answer 19

yep

Answer 20

Go ahead, I see to the extent that what can I do in that.. :)

Answer 21

did it by using cramers rule

Answer 22

You can do by this approach too.. All are same.
In first equation, find B..
Put that B in second equation, by doing so, you will get only A and C in second equation.
and third equation is already having A and C, so just use the same approach used by me here.. Find A first, put it in third equation, you get C and again you get A, finally you get B. :P

Answer 23

Ask your question, if you want to post then you can post it here itself..