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Using the following equation: Pb (SO4)2 + 4 LiNO3 --> Pb(NO3)4 + 2 Li2SO4 How many grams of lithium nitrate will be needed to make 250 grams of lithium sulfate, assuming that you have an adequate amount of lead(IV) sulfate to do the reaction?
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Calculate, how Many moles is 250 g Lithium sulphate. Amount of moles of Lithium nitrate needed is twice of that. Then you need to Multiply number of moles by molar mass of LiNO3
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