D'Andre has decided that he needs to get more exercise, so he is building a running regimen for himself. He decides that, beginning on Sunday, he will run 10 feet. On each subsequent day, he will double the distance he ran the previous day. So we will run 20 feet on Monday, 40 feet on Tuesday and so on. His track coach (who also happens to be his math teacher) told D'Andre that he won't be able to keep to his plans for very long, but D'Andre is determined to make it work for at least two weeks.
I found that according to his plan, he will run about 81920 feet or 15.5 miles on the 14th day using this formula (conversion = feet/5280) \[10*2^{(14-1)}\] The only thing I have left to find is how far he will have to run total in those two weeks. Thanks!
so you cant oslve just that equation?
Do I just do \[(10\frac {2^{14}-1}{(2-1)})/5280\] If I do that, I get about 31 miles
That is how far he runs just that day in the first part.
i got 15
For the second part?
If so, that won't work. He runs over 15 miles \(just\) on the 14th day. I thought that was it too but then I found that it wouldn't work. I used \[a\frac{r^n-1}{r-1}\] where a is 10 because that is the starting number and r=2. n would be 14 because that is the last day.
then divided that answer by 5280
what's the formula for the geometric series?
The one I used to get the 14th day?
\[10*2^{(n-1)}\]
oh that's the one already sooo let's seee yes, everything that you did looks right ? so which part are you not sure of?
\(a\frac{r^n-1}{r-1}\) just apply this formula to get the sum and convert it to the proper unit
I just wanted to check the second part hehe xD Thanks!
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