You place a balloon in a closed chamber at standard temperature and pressure (STP). You double the chamber temperature while leaving the pressure constant. What happens to the balloon?

It doubles in volume.

It decreases to one-half of its original volume.

It stays the same volume.

It expands to four times its original volume.

Question

You place a balloon in a closed chamber at standard temperature and pressure (STP). You double the chamber temperature while leaving the pressure constant. What happens to the balloon?

       It doubles in volume.

       It decreases to one-half of its original volume.

       It stays the same volume.

       It expands to four times its original volume.

anonymous · Answer

@YOUNGSUPERMAN

youngsuperman · Answer

b

anonymous · Answer

you sure?

And can you help with more? I have a lot ;-;

anonymous · Answer

@Baby_bear

anonymous · Answer

@baby_bear69

anonymous · Answer

You place air in a sealed can at standard temperature and pressure (STP). You triple its absolute temperature (K) while leaving the volume constant. What happens to the pressure?
(Points : 3)
       It triples.

       It decreases by one-half.

       It stays the same.

       It decreases to one-third of the original pressure.

youngsuperman · Answer

u still need a little help

anonymous · Answer

Now Im confused 





@just_one_last_goodbye

youngsuperman · Answer

@Baby_Bear69 did u get wat i said

baby_bear69 · Answer

Mike is right, the first one is B

anonymous · Answer

Okay, this is so confusing >_<

baby_bear69 · Answer

the second one is A

anonymous · Answer

you sure?

just_one_last_goodbye · Answer

o.o hey babe which one u want me to do? (for that very special reward better than a medal)

anonymous · Answer

Welp you wont get it for just one question ;)

anonymous · Answer

Which of the following is the mathematical representation of Boyle's law?
(Points : 3)
       P1V1 = P2V2

       P1V1 = V2/T2

       V1/T1 = V2/T2

       P1/T1 = P2/T2

baby_bear69 · Answer

o.o

just_one_last_goodbye · Answer

o.o gotta be kidding me bruh...

just_one_last_goodbye · Answer

got a probelm with something @Baby_Bear69

baby_bear69 · Answer

no?

anonymous · Answer

Nope. Im not.

just_one_last_goodbye · Answer

good =.=

baby_bear69 · Answer

we used to be friends..  what happened.? & Leila, the first two that i answered i'm pretty sure are right..

anonymous · Answer

Okay and the third? Im sorry angel but when it comes to chem im a dimwit >_>

just_one_last_goodbye · Answer

Third is P1V1 = p2V2 (choice A)

anonymous · Answer

Okay, thank you!! You guys up for helping me finish this?

At room temperature, which of the following is the most compressible?
(Points : 3)
       one liter of mercury, a liquid

       one liter of iron, a solid

       one liter of oxygen, a gas

       one liter of water, a liquid

anonymous · Answer

its 15 problems o-o

youngsuperman · Answer

c i think

just_one_last_goodbye · Answer

^ agreed Only gasses are compressible.

anonymous · Answer

okay thank youuuu!!!


You open a can of soda at room temperature and hear a hiss. Which of the following factors has changed inside the container?
(Points : 3)
       pressure of gas

       temperature of gas

       type of gas

       atmospheric pressure

anonymous · Answer

A?

baby_bear69 · Answer

i would say A

just_one_last_goodbye · Answer

I would say D

anonymous · Answer

...o-o?

youngsuperman · Answer

yea meetoo

anonymous · Answer

So its D?

just_one_last_goodbye · Answer

hey is did i reach my reward yet? Leila

baby_bear69 · Answer

I'm sticking with A but D might be right

anonymous · Answer

Soon captain...soon xD


I think D makes a little more sense

somy · Answer

@LeilaJudeh  One question per post please!

anonymous · Answer

=_=

somy · Answer

+ second question you got the wrong answer 

***sorry but those are OS rules, a q per post

just_one_last_goodbye · Answer

@Somy there really isn't a rule for that

anonymous · Answer

Can you just turn a blind eye at this, i dont wanna close >_<

just_one_last_goodbye · Answer

o_o u say that theres a rule for that but... the CoC doesn't say anything

anonymous · Answer

0-0 so I dont have to close!! okay next question ^_^


Which of the following is the mathematical representation of Gay-Lussac's law?
(Points : 3)
       P1V1 = V2/T2

       P1/T1 = P2/T2

       V1/T1 = V2/T2

       P1V1 = P2V2

anonymous · Answer

I put B on that

somy · Answer

Can of soda is also wrong if you chose D

anonymous · Answer

o-o

just_one_last_goodbye · Answer

@Somy how so? I know the outer atmosphere doesn't do anything to the can but the atmosphere in the inside of the can yes it does.

somy · Answer

The pressure of the gas inside the can is lower than that of outside 
which is why when you open the can the gas particles rush out 
the question is asking about pressure inside the can so as particles rush out= the pressure will decrease

somy · Answer

+ @LeilaJudeh  is this an online test?

anonymous · Answer

Nope study guide

somy · Answer

hmmmm then 
do you understand each question u've asked so far?

somy · Answer

why is which answer

anonymous · Answer

Yes teacher, I have ^_^

somy · Answer

lol that teacher doe 
just make sure you learn, & dont cheat 
it won't take you anywhere in future/adult world T_T

anonymous · Answer

I know ^_^

Ty for caring <33

somy · Answer

:)

somy · Answer

Good luck!

anonymous · Answer

Thank you!

anonymous · Answer

so captain you still up to help?

somy · Answer

sure but please can you open a new q T_T coz its a pain going all the way down

anonymous · Answer

okay xD