Question

What is the probability that a point chosen inside the large rectangle is not in the shaded region?

18%
36%
42%
64%

Answer 1

lel hi!

Answer 2

It worked!!!

Answer 3

@sammixboo

Answer 4

Okay

Answer 5

@sammixboo

Answer 6

I'll summon u l8tr @Dodgegirl :) when I get 2 a diff question

Answer 7

Okay just lemme know c:

Answer 8

Ugh i totally forgot how to do this give me a second to refresh my memory xD

Answer 9

:) I will

Answer 10

Sorry i am no help here. As i solve equations, time lines ETC. I solve a bunch but i dont usually do geometry involved things.

Answer 11

ok :)

Answer 12

@sammixboo can you please help me??

Answer 13

@Directrix @freckles

Answer 14

you will need to find some areas here

Answer 15

ok

Answer 16

find the larger area and the smaller area

Answer 17

for the smaller one, its 18 units

Answer 18

and for the bigger one, its 50

Answer 19

right?

Answer 20

so now you can find the area of the unshaded region

Answer 21

10 on the long side, 10 on the other long side, and 10 on the short, 10 on the other short side lol i divided them into parts

Answer 22

so 40

Answer 23

\[\frac{\text{ area of non-shaded region}}{\text{ area of largest rectangle there }}\]
will be the probability of the point inside the largest rectangle there occurs in the shaded region

Answer 24

wait what ?

Answer 25

the area of the nonshaded region is just the difference in areas of the rectangles you found

Answer 26

yeah

Answer 27

ugh nvrmind about the last part lol

Answer 28

so the area of the non-shaded region is?

Answer 29

i think its 40?

Answer 30

you think that is the difference of 50 and 18?

Answer 31

oh, nonono!!! lol sorry i misunderstood

Answer 32

32

Answer 33

yes the area of the nonshaded region is 32 units squared

Answer 34

Ok

Answer 35

so remember what you see is the the area of the nonshaded area/the larger rectangle area

Answer 36

ok

Answer 37

ok any questions

Answer 38

nope

Answer 39

wow is that it??

Answer 40

what did you get as the answer?

Answer 41

oh yeah, one last question,

Answer 42

how do i find that part lol??

Answer 43

so i guess that means you didn't understand anything I said above :p

Answer 44

i will copy and paste what I said one more time
\[\frac{\text{ area of non-shaded region}}{\text{ area of largest rectangle there }}\]
will be the probability of the point inside the largest rectangle there occurs in the shaded region

--
can i ask why this doesn't make sense?

Answer 45

also that is suppose to say nonshaded region*

Answer 46

how do I do that???? the probability part is hardest :(

Answer 47

you found the area of the non-shaded region already
and you found the area of the large rectangle...

Answer 48

ok, sooo

Answer 49

What is the probability that a point chosen inside the large rectangle is not in the shaded region?

18%
36%
42%
64%

Answer 50

you see where it says area of non-shaded region?
that is on top of the fraction there...and remember you got 32 for the top

and you also found the bottom, that is the area of the larger rectangle to be 50

Answer 51

like I know you can replace a group of words with a number you found those group of words to mean

Answer 52

yeah of course

Answer 53

ohohoh

Answer 54

32/50

Answer 55

now i have to divide right??

Answer 56

\[\frac{\text{ area of non-shaded region}}{\text{ area of largest rectangle there }} \]
will be the probability of the point inside the largest rectangle there occurs in the non-shaded region
replace the group of words "area of nonshadead region" with what you found that area to be which is 32
area of nonshaded region=32

you found the area of largest rectangle to be 50 so replace that group of words with 50

so you have 32/50
the division I leave to you

Answer 57

.64 which = to 64% right??

Answer 58

ok great

Answer 59

yes!!!!!!!!!!! thx:)

Answer 60

directrix and I commented on your previous question by the way

Answer 61

oh ok ill check it out