Which of the following is the mathematical representation of Gay-Lussac's law? (Points : 3) P1V1 = V2/T2 P1/T1 = P2/T2 V1/T1 = V2/T2 P1V1 = P2V2
@Somy I chose B
you are right :3
Thank you! ^_^
A student increases the temperature of a 300 cm3 balloon from 30°C to 60°C. What will the new volume of the balloon be? (Remember to be careful with the units.) (Points : 3) 273 cm3 300 cm3 600 cm3 329 cm3
which formula would you use for this? you have volume and temperature
i have no clue
okay remember this formula also : Charles Law \[\sf \frac{ V_1 }{ T_1 } = \frac{ V_2 }{ T_2 }\]
you are given V1 T1 T2 you have to find V2 units for this formula are: V = m3 T = Kelvin
so whats v1 t` and t2?
V 1 is initial volume T1 is initial temperature
V2 is final volume and T2 is final temperature
Okay so I would have to do the fishtail division we learned in third frade for this?
grade**
I always choose the safe zone when it comes to units which is why i told you to use the SI unit system so first convert the units to ones i told you and then calculate using that formula & yes do this 3rd grade calculation AFTER converting to appropriate units
your final answer for volume will be in m3 so convert it to cm3 to match one of the options
i am so so confused
is it C?
Confused? lol u said grade 3 calculation :P okay look T is given to you in Celsius and to convert it to Kelvin all you need to do is add 273 to Celsius value
1cm3 = 1.0 × 10-6 m3 300cm3 = X? m3 X= 300 × ( 1.0 × 10-6) so find it
once you find it \[\sf \frac{ V_1 }{ T_1 } = \frac{ V_2 }{ T_2 }\] you need V2 so rearrange the formula \[V_2 = \frac{ V_1 \times T_2 }{ T_1 }\]
try solving now
ITS STILL CONFUSING. SO VERY CONFUSING. I dont get it. =.=
okay, which part you dont get?
From the very beginning to the very end
do you get the formula?
What I get is I have to plug things in to get the answer. thats it
so you dont get the units conversion
okay i'll make it easy for you since you dont get units forget about unit of volume leave it as cm3 only change the temp 30°C +237 = 303 K = T1 60°C +273 = 333 K = T2 V1 = 300 cm3 use the formula do grade 3 calculation \[\sf V_2 = \frac{ V_1 \times T_2 }{ T_1 }\] \[\sf V_2 = \frac{ 300 \times 333 }{ 303 }\]
does it make sense now?
sorry the internet blew out
its okay, more importantly, did you get it?
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