Question

a ball is thrown at a 30 degree angle above the horizontal with a speed of 3 m/s. after .5 s the horizontal component of its velocity will be...

Answer 1

Is their more to the question?

Answer 2

a) 1.5 m/s
b) 2.6 m/s
c) 4.9 m/s
d) 5.5 m/s
e) 6.0 m/s

Answer 3

M/s so i pluged in 30 divded by 0.5 and its 6.0

Answer 4

You need to deconstruct the velocity into it's horizontal and vertical components. You need trigonometry to do this. For a projectile, the horizontal velocity will be the same for the entire flight. Have a look at this picture:



We want to find x, the horizontal component of the velocity. You can see this is a right angle triangle, so you can find x using this:

\[\cos 30=\frac{x}{3}\]

Solving for x, you should get 2.6 m/s. That makes B your answer! If you have any questions let me know.

Answer 5

ah, thank you matt, I was solving it using sin instead of cos.