The coordinates below represent two linear equations. How many solutions does this system of equations have? Line 1 x y –3 5 0 4 Line 2 x y 0 4 6 2 A. 0 B. exactly 1 C. exactly 2 D. infinitely many
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well, you could start off by getting their slopes if their slopes are equal, they're parallel lines, thus they do not intersect, thus no solution if not, then they do touch, thus 1 solution
So A? @jdoe0001
hmmm well.. what slopes did you get?
for line 1 -3,4
3,4? may want to revise your slopes
\(\large { \begin{array}{ccllll} x&y \\\hline\\ {\color{red}{ -3}}&{\color{blue}{ 5}}\\ {\color{red}{ 0}}&{\color{blue}{ 4}} \end{array}\qquad \begin{array}{ccllll} x&y \\\hline\\ {\color{red}{ 0}}&{\color{blue}{ 2}}\\ {\color{red}{ 4}}&{\color{blue}{ 6}} \end{array}\qquad slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}} }\)
-3y-0y/0x-4x
or is it -3y-4y/2x-6x
hmm shoot I got the numbers off
its okay
anyhow... you'd need to get the slopes first for each \(\large { \begin{array}{ccllll} x&y \\\hline\\ {\color{red}{ -3}}&{\color{blue}{ 5}}\\ {\color{red}{ 0}}&{\color{blue}{ 4}} \end{array}\qquad \begin{array}{ccllll} x&y \\\hline\\ {\color{red}{ 0}}&{\color{blue}{ 4}}\\ {\color{red}{ 6}}&{\color{blue}{ 2}} \end{array}\qquad slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}} }\)
if the slopes are equal, no solution, or infinite solutions if they differ, then 1 solution
i understand that i just dont understand slope
well... if you have not covered slopes yet... how are you meant to find whether they have solution or not then? that is, what is the chapter section covering to do so?
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