Question

If F'(x) = (1+t^3)^0.5 and F(1) = 5, then F(3) =

A. 1.230
B. 3.585
C. 6.230
D. 8.535
E. 11.230

Answer 1

\[
F(3)-F(1) = \int_1^3F'(x)~dx
\]

Answer 2

This means: \[
F(3) - 5 = \int_1^3 (1+t^3)^{0.5}~dx
\]Though I have a hunch they meant to say \(F'(t) = (1+t^3)^{0.5}\)

Answer 3

\[
F(3) = \int_1^3\sqrt{1+t^3}~dt + 5
\]

Answer 4

Thank you!