PLEASE HELP ITS DUE TODAY

Question

anonymous · Answer

A 1,730 KG car traveling at a rate of 166 Kph is racing around a flat circular track, maintaining a perfectly circular 2 Km path.
a) what is the centripetal force acting on the car?
b) what is the minimum coefficient of statistic friction between the tires and the track that will maintain this situation?

anonymous · Answer

a) using the formula Fc= mv^2/r    

Fc= centrpetal force
m= mass in kg
v= speed in m/s
r= circular distance in m

anonymous · Answer

forgot ho to obtain coeff sorry

shamim · Answer

Given 
m=1730kg
v=166kmh=?m/s
2*pi*r=2000
r=?
Fc=?

matt101 · Answer

Funny...I answered this exact question not too long ago: http://openstudy.com/study#/updates/54f92f97e4b0f8f325f78cf7