Question

A ball of mass 8kg is dropped from a height of 10.What is the velocity with which it strikes the ground.

Answer 1

you may use conservation of energy :
\[mgh = \dfrac{1}{2}mv^2 \implies v = \sqrt{2gh}\]

Answer 2

??????????????????????

Answer 3

what is 'g'?
@ganeshie8

Answer 4

\(g\) is acceleration due to gravity

Answer 5

10 ms?

Answer 6

g = 10 m/s^2 will do

http://en.wikipedia.org/wiki/Gravity_of_Earth

Answer 7

solve?

Answer 8

Cant I use
mgh = mv^2/2?

Answer 9

@ganeshie8

Answer 10

@ganeshie8

Answer 11

yes

Answer 12

So now?

Answer 13

mgh = mv^2/2?

cancel m both sides, what do u get ?

Answer 14

10 x 10 = 1/2 x v^2

Answer 15

yes solve v

Answer 16

50 = v^2?

Answer 17

nope

Answer 18

200 = v^2

Answer 19

yes

Answer 20

take squareroot and finish it off

Answer 21

sqrt200 = v

Answer 22

\[v = \sqrt200\]