Question

Whats the inverse of f(x)?

f(x)=-4x^2+1

Answer 1

HI!!

Answer 2

solve
\[x=-4y^2+1\] in 3 steps

Answer 3

subtract 1, \[x-1=-4y^2\]

Answer 4

divide by \(-4\)
\[\frac{1-x}{4}=y^2\]

Answer 5

take the square root
don't forget the \(\pm\)

Answer 6

hmmm
what happens when the function is different?
how about give the concept about inverse functions :)

Answer 7

what happens when the function is different?

Answer 8

i guess it is a different function

Answer 9

the inverse is not a function, because your function is not one to one
but i guess you can still write it if you like

Answer 10

still a little lost.. but i got the whole thing about switching the x and the y...

Answer 11

once you switch them you need to solve for \(y\)

Answer 12

\[x=-4y^2+1\]is what you get when you switch them

Answer 13

then to get \(y\) you need to get rid of the 1 on the right,
subtract one gives you
\[x-1=-4y^2\]

Answer 14

so the inverse would be.. f^-1(x)= +- sqr1-x/2

Answer 15

yes it would be
\[\frac{\pm\sqrt{1-x}}{2}\]

Answer 16

it is not really a function, so it is a bit silly to write
\[f^{-1}(x)=\frac{\pm\sqrt{1-x}}{2}\]

Answer 17

btw what happened to your instagram?

Answer 18

@satellite73 whatcha mean?