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Algebra 12 Online
OpenStudy (anonymous):

Hello, I'm taking AlgebraX at edX.org. I'm not really understanding how to this kind of problem works, if anyone could help I'd appreciate it, thanks. They give the answer, I just don't understand how they got it. If n**5 =3, then what is the value of n**10? Hint: Recall that (n**5)**2=n**10.

OpenStudy (ositan):

Considering that n**5=3 and 2*5=10, I really want to say that the value of n**10 is 6. However, to help support that, one can replace the (n**5) in (n**5)**2 with a 3, and then you get 3**2. 3(2)=6, so that's my logic. Anyone got anything else?

OpenStudy (perl):

i agree, unless ** refers to some unusual operation. lets assume that ** = normal multiplication. then n**10 = 6

OpenStudy (anonymous):

Sorry ** means n raised to the power of something, So n**5 = n raised to the power of 5.

OpenStudy (anonymous):

n**5 = n^5

OpenStudy (ositan):

Ah. If you want to do that on here, either use the LaTeX functions, or use this: ^

OpenStudy (perl):

oh in that case...

OpenStudy (anonymous):

My brain gets stuck in python mode and ** is what python uses, sorry.

OpenStudy (ositan):

PYTHON! Alright, you're forgiven.

OpenStudy (perl):

If n^5 = 3 then (n^5)^2 = 3^2 = 9 by substituting 3 for n^5. But (n^5)^2 = n^(5*2) = n^(10) by property of exponents. Therefore n^(10) = 9

OpenStudy (anonymous):

Got it, the a-ha click moment just happened, thank.

OpenStudy (perl):

:)

OpenStudy (anonymous):

The reason I'm going back and taking Algebra again is because of Python, I was having trouble following the math. I've got to say edX and openstudy are amazing resources.

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